Dart 速查表
- 字符串插值
- 可空变量
- 空感知运算符
- 条件属性访问
- 集合字面量
- 箭头语法
- 级联
- Getter 和 Setter
- 可选位置参数
- 命名参数
- 异常
- 在构造函数中使用 this
- 初始化列表
- 命名构造函数
- 工厂构造函数
- 重定向构造函数
- 常量构造函数
- 下一步是什么?
Dart 语言旨在易于来自其他语言的程序员学习,但它有一些独特的特性。本教程将引导您了解其中最重要的语言特性。
本教程中的嵌入式编辑器包含部分完成的代码片段。您可以使用这些编辑器通过完成代码并点击**运行**按钮来测试您的知识。编辑器还包含完整的测试代码;**不要编辑测试代码**,但可以随意研究它以了解测试。
如果您需要帮助,请展开每个 DartPad 下方的**...的解决方案**下拉菜单以获取解释和答案。
字符串插值
#要将表达式的值放在字符串中,请使用${expression}
。如果表达式是标识符,则可以省略{}
。
以下是一些使用字符串插值的示例
字符串 | 结果 |
---|---|
'${3 + 2}' | '5' |
'${"word".toUpperCase()}' | 'WORD' |
'$myObject' | myObject.toString() 的值 |
代码示例
#以下函数以两个整数作为参数。使其返回一个包含两个整数并用空格分隔的字符串。例如,stringify(2, 3)
应返回'2 3'
。
String stringify(int x, int y) {
TODO('Return a formatted string here');
}
// Tests your solution (Don't edit!):
void main() {
assert(stringify(2, 3) == '2 3',
"Your stringify method returned '${stringify(2, 3)}' instead of '2 3'");
print('Success!');
}
字符串插值示例的解决方案
x
和y
都是简单值,Dart 的字符串插值将处理将其转换为字符串表示形式。您只需使用$
运算符在单引号内引用它们,并在它们之间添加一个空格即可
String stringify(int x, int y) {
return '$x $y';
}
可空变量
#Dart 强制执行健全的空安全。这意味着值不能为 null,除非您声明它们可以为 null。换句话说,类型默认为不可为空。
例如,考虑以下代码。在空安全的情况下,此代码会返回错误。类型为int
的变量不能具有值null
int a = null; // INVALID.
在创建变量时,在类型后添加?
以指示变量可以为null
int? a = null; // Valid.
您可以稍微简化一下代码,因为在所有版本的 Dart 中,null
都是未初始化变量的默认值
int? a; // The initial value of a is null.
要了解有关 Dart 中空安全的更多信息,请阅读健全的空安全指南。
代码示例
#在此 DartPad 中声明两个变量
- 一个名为
name
的可空String
,其值为'Jane'
。 - 一个名为
address
的可空String
,其值为null
。
忽略 DartPad 中的所有初始错误。
// TODO: Declare the two variables here
// Tests your solution (Don't edit!):
void main() {
try {
if (name == 'Jane' && address == null) {
// verify that "name" is nullable
name = null;
print('Success!');
} else {
print('Not quite right, try again!');
}
} catch (e) {
print('Exception: ${e.runtimeType}');
}
}
可空变量示例的解决方案
将这两个变量声明为String
后跟?
。然后,将'Jane'
赋值给name
,并将address
保留为未初始化状态
String? name = 'Jane';
String? address;
空感知运算符
#Dart 提供了一些方便的运算符来处理可能为 null 的值。其中一个是??=
赋值运算符,它仅在变量当前为 null 时才将值赋给变量
int? a; // = null
a ??= 3;
print(a); // <-- Prints 3.
a ??= 5;
print(a); // <-- Still prints 3.
另一个空感知运算符是??
,它返回其左侧的表达式,除非该表达式的值为 null,在这种情况下,它会计算并返回其右侧的表达式
print(1 ?? 3); // <-- Prints 1.
print(null ?? 12); // <-- Prints 12.
代码示例
#尝试替换??=
和??
运算符,以在以下代码段中实现所描述的行为。
忽略 DartPad 中的所有初始错误。
String? foo = 'a string';
String? bar; // = null
// Substitute an operator that makes 'a string' be assigned to baz.
String? baz = foo /* TODO */ bar;
void updateSomeVars() {
// Substitute an operator that makes 'a string' be assigned to bar.
bar /* TODO */ 'a string';
}
// Tests your solution (Don't edit!):
void main() {
try {
updateSomeVars();
if (foo != 'a string') {
print('Looks like foo somehow ended up with the wrong value.');
} else if (bar != 'a string') {
print('Looks like bar ended up with the wrong value.');
} else if (baz != 'a string') {
print('Looks like baz ended up with the wrong value.');
} else {
print('Success!');
}
} catch (e) {
print('Exception: ${e.runtimeType}.');
}
}
空感知运算符示例的解决方案
在此练习中,您需要做的就是在TODO
注释中替换??
或??=
。阅读上面的文字以确保您了解两者,然后试一试
// Substitute an operator that makes 'a string' be assigned to baz.
String? baz = foo ?? bar;
void updateSomeVars() {
// Substitute an operator that makes 'a string' be assigned to bar.
bar ??= 'a string';
}
条件属性访问
#要保护对可能为 null 的对象的属性或方法的访问,请在点 (.
) 之前放置一个问号 (?
)
myObject?.someProperty
前面的代码等效于以下代码
(myObject != null) ? myObject.someProperty : null
您可以在单个表达式中将多个?.
连在一起
myObject?.someProperty?.someMethod()
如果myObject
或myObject.someProperty
为 null,则前面的代码返回 null(并且永远不会调用someMethod()
)。
代码示例
#以下函数以可空字符串作为参数。尝试使用条件属性访问使其返回str
的大写版本,或者如果str
为null
则返回null
。
String? upperCaseIt(String? str) {
// TODO: Try conditionally accessing the `toUpperCase` method here.
}
// Tests your solution (Don't edit!):
void main() {
try {
String? one = upperCaseIt(null);
if (one != null) {
print('Looks like you\'re not returning null for null inputs.');
} else {
print('Success when str is null!');
}
} catch (e) {
print('Tried calling upperCaseIt(null) and got an exception: \n ${e.runtimeType}.');
}
try {
String? two = upperCaseIt('a string');
if (two == null) {
print('Looks like you\'re returning null even when str has a value.');
} else if (two != 'A STRING') {
print('Tried upperCaseIt(\'a string\'), but didn\'t get \'A STRING\' in response.');
} else {
print('Success when str is not null!');
}
} catch (e) {
print('Tried calling upperCaseIt(\'a string\') and got an exception: \n ${e.runtimeType}.');
}
}
条件属性访问示例的解决方案
如果此练习希望您有条件地将字符串转换为小写,则可以这样操作:str?.toLowerCase()
。使用等效的方法将字符串转换为大写!
String? upperCaseIt(String? str) {
return str?.toUpperCase();
}
集合字面量
#Dart 内置支持列表、映射和集合。您可以使用字面量创建它们
final aListOfStrings = ['one', 'two', 'three'];
final aSetOfStrings = {'one', 'two', 'three'};
final aMapOfStringsToInts = {
'one': 1,
'two': 2,
'three': 3,
};
Dart 的类型推断可以为您分配这些变量的类型。在这种情况下,推断的类型为List<String>
、Set<String>
和Map<String, int>
。
或者您可以自己指定类型
final aListOfInts = <int>[];
final aSetOfInts = <int>{};
final aMapOfIntToDouble = <int, double>{};
当您使用子类型的內容初始化列表但仍希望列表为List<BaseType>
时,指定类型非常方便
final aListOfBaseType = <BaseType>[SubType(), SubType()];
代码示例
#尝试将以下变量设置为指示的值。替换现有的 null 值。
// Assign this a list containing 'a', 'b', and 'c' in that order:
final aListOfStrings = null;
// Assign this a set containing 3, 4, and 5:
final aSetOfInts = null;
// Assign this a map of String to int so that aMapOfStringsToInts['myKey'] returns 12:
final aMapOfStringsToInts = null;
// Assign this an empty List<double>:
final anEmptyListOfDouble = null;
// Assign this an empty Set<String>:
final anEmptySetOfString = null;
// Assign this an empty Map of double to int:
final anEmptyMapOfDoublesToInts = null;
// Tests your solution (Don't edit!):
void main() {
final errs = <String>[];
if (aListOfStrings is! List<String>) {
errs.add('aListOfStrings should have the type List<String>.');
} else if (aListOfStrings.length != 3) {
errs.add('aListOfStrings has ${aListOfStrings.length} items in it, \n rather than the expected 3.');
} else if (aListOfStrings[0] != 'a' || aListOfStrings[1] != 'b' || aListOfStrings[2] != 'c') {
errs.add('aListOfStrings doesn\'t contain the correct values (\'a\', \'b\', \'c\').');
}
if (aSetOfInts is! Set<int>) {
errs.add('aSetOfInts should have the type Set<int>.');
} else if (aSetOfInts.length != 3) {
errs.add('aSetOfInts has ${aSetOfInts.length} items in it, \n rather than the expected 3.');
} else if (!aSetOfInts.contains(3) || !aSetOfInts.contains(4) || !aSetOfInts.contains(5)) {
errs.add('aSetOfInts doesn\'t contain the correct values (3, 4, 5).');
}
if (aMapOfStringsToInts is! Map<String, int>) {
errs.add('aMapOfStringsToInts should have the type Map<String, int>.');
} else if (aMapOfStringsToInts['myKey'] != 12) {
errs.add('aMapOfStringsToInts doesn\'t contain the correct values (\'myKey\': 12).');
}
if (anEmptyListOfDouble is! List<double>) {
errs.add('anEmptyListOfDouble should have the type List<double>.');
} else if (anEmptyListOfDouble.isNotEmpty) {
errs.add('anEmptyListOfDouble should be empty.');
}
if (anEmptySetOfString is! Set<String>) {
errs.add('anEmptySetOfString should have the type Set<String>.');
} else if (anEmptySetOfString.isNotEmpty) {
errs.add('anEmptySetOfString should be empty.');
}
if (anEmptyMapOfDoublesToInts is! Map<double, int>) {
errs.add('anEmptyMapOfDoublesToInts should have the type Map<double, int>.');
} else if (anEmptyMapOfDoublesToInts.isNotEmpty) {
errs.add('anEmptyMapOfDoublesToInts should be empty.');
}
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
// ignore_for_file: unnecessary_type_check
}
集合字面量示例的解决方案
在每个等号后添加列表、集合或映射字面量。请记住为空声明指定类型,因为它们无法推断出来。
// Assign this a list containing 'a', 'b', and 'c' in that order:
final aListOfStrings = ['a', 'b', 'c'];
// Assign this a set containing 3, 4, and 5:
final aSetOfInts = {3, 4, 5};
// Assign this a map of String to int so that aMapOfStringsToInts['myKey'] returns 12:
final aMapOfStringsToInts = {'myKey': 12};
// Assign this an empty List<double>:
final anEmptyListOfDouble = <double>[];
// Assign this an empty Set<String>:
final anEmptySetOfString = <String>{};
// Assign this an empty Map of double to int:
final anEmptyMapOfDoublesToInts = <double, int>{};
箭头语法
#你可能在 Dart 代码中见过 =>
符号。这个箭头语法是一种定义函数的方式,它执行右侧的表达式并返回其值。
例如,考虑一下对 List
类的 any()
方法的调用
bool hasEmpty = aListOfStrings.any((s) {
return s.isEmpty;
});
以下是用更简单的方式编写该代码的方法
bool hasEmpty = aListOfStrings.any((s) => s.isEmpty);
代码示例
#尝试完成以下使用箭头语法的语句。
class MyClass {
int value1 = 2;
int value2 = 3;
int value3 = 5;
// Returns the product of the above values:
int get product => TODO();
// Adds 1 to value1:
void incrementValue1() => TODO();
// Returns a string containing each item in the
// list, separated by commas (e.g. 'a,b,c'):
String joinWithCommas(List<String> strings) => TODO();
}
// Tests your solution (Don't edit!):
void main() {
final obj = MyClass();
final errs = <String>[];
try {
final product = obj.product;
if (product != 30) {
errs.add('The product property returned $product \n instead of the expected value (30).');
}
} catch (e) {
print('Tried to use MyClass.product, but encountered an exception: \n ${e.runtimeType}.');
return;
}
try {
obj.incrementValue1();
if (obj.value1 != 3) {
errs.add('After calling incrementValue, value1 was ${obj.value1} \n instead of the expected value (3).');
}
} catch (e) {
print('Tried to use MyClass.incrementValue1, but encountered an exception: \n ${e.runtimeType}.');
return;
}
try {
final joined = obj.joinWithCommas(['one', 'two', 'three']);
if (joined != 'one,two,three') {
errs.add('Tried calling joinWithCommas([\'one\', \'two\', \'three\']) \n and received $joined instead of the expected value (\'one,two,three\').');
}
} catch (e) {
print('Tried to use MyClass.joinWithCommas, but encountered an exception: \n ${e.runtimeType}.');
return;
}
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
}
箭头语法示例的解决方案
对于 product,你可以使用 *
将三个值相乘。对于 incrementValue1
,你可以使用自增运算符 (++
)。对于 joinWithCommas
,请使用 List
类中的 join
方法。
class MyClass {
int value1 = 2;
int value2 = 3;
int value3 = 5;
// Returns the product of the above values:
int get product => value1 * value2 * value3;
// Adds 1 to value1:
void incrementValue1() => value1++;
// Returns a string containing each item in the
// list, separated by commas (e.g. 'a,b,c'):
String joinWithCommas(List<String> strings) => strings.join(',');
}
级联
#要在同一对象上执行一系列操作,请使用级联 (..
)。我们都见过这样的表达式
myObject.someMethod()
它在 myObject
上调用 someMethod()
,表达式的结果是 someMethod()
的返回值。
以下是使用级联的相同表达式
myObject..someMethod()
尽管它仍然在 myObject
上调用 someMethod()
,但表达式的结果**不是**返回值——而是对 myObject
的引用!
使用级联,你可以将原本需要单独语句的操作链接在一起。例如,考虑以下代码,它使用条件成员访问运算符 (?.
) 在 button
不为 null
时读取其属性
var button = querySelector('#confirm');
button?.text = 'Confirm';
button?.classes.add('important');
button?.onClick.listen((e) => window.alert('Confirmed!'));
button?.scrollIntoView();
要改为使用级联,你可以从空值短路级联 (?..
) 开始,它保证不会在 null
对象上尝试任何级联操作。使用级联可以缩短代码并使 button
变量变得不必要
querySelector('#confirm')
?..text = 'Confirm'
..classes.add('important')
..onClick.listen((e) => window.alert('Confirmed!'))
..scrollIntoView();
代码示例
#使用级联创建一个单一语句,将 BigObject
的 anInt
、aString
和 aList
属性分别设置为 1
、'String!'
和 [3.0]
,然后调用 allDone()
。
class BigObject {
int anInt = 0;
String aString = '';
List<double> aList = [];
bool _done = false;
void allDone() {
_done = true;
}
}
BigObject fillBigObject(BigObject obj) {
// Create a single statement that will update and return obj:
return TODO('obj..');
}
// Tests your solution (Don't edit!):
void main() {
BigObject obj;
try {
obj = fillBigObject(BigObject());
} catch (e) {
print('Caught an exception of type ${e.runtimeType} \n while running fillBigObject');
return;
}
final errs = <String>[];
if (obj.anInt != 1) {
errs.add(
'The value of anInt was ${obj.anInt} \n rather than the expected (1).');
}
if (obj.aString != 'String!') {
errs.add(
'The value of aString was \'${obj.aString}\' \n rather than the expected (\'String!\').');
}
if (obj.aList.length != 1) {
errs.add(
'The length of aList was ${obj.aList.length} \n rather than the expected value (1).');
} else {
if (obj.aList[0] != 3.0) {
errs.add(
'The value found in aList was ${obj.aList[0]} \n rather than the expected (3.0).');
}
}
if (!obj._done) {
errs.add('It looks like allDone() wasn\'t called.');
}
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
}
级联示例的解决方案
此练习的最佳解决方案以 obj..
开头,并具有四个链接在一起的赋值操作。从 return obj..anInt = 1
开始,然后添加另一个级联 (..
) 并开始下一个赋值。
BigObject fillBigObject(BigObject obj) {
return obj
..anInt = 1
..aString = 'String!'
..aList.add(3)
..allDone();
}
Getter 和 Setter
#无论何时需要对属性进行比简单字段更多的控制,你都可以定义 getter 和 setter。
例如,你可以确保属性的值有效
class MyClass {
int _aProperty = 0;
int get aProperty => _aProperty;
set aProperty(int value) {
if (value >= 0) {
_aProperty = value;
}
}
}
你还可以使用 getter 定义计算属性
class MyClass {
final List<int> _values = [];
void addValue(int value) {
_values.add(value);
}
// A computed property.
int get count {
return _values.length;
}
}
代码示例
#假设你有一个购物车类,它保留了一个 List<double>
的价格列表。添加以下内容
- 一个名为
total
的 getter,它返回价格的总和 - 一个 setter,它用一个新的列表替换旧列表,只要新列表不包含任何负价格(在这种情况下,setter 应该抛出一个
InvalidPriceException
)。
忽略 DartPad 中的所有初始错误。
class InvalidPriceException {}
class ShoppingCart {
List<double> _prices = [];
// TODO: Add a "total" getter here:
// TODO: Add a "prices" setter here:
}
// Tests your solution (Don't edit!):
void main() {
var foundException = false;
try {
final cart = ShoppingCart();
cart.prices = [12.0, 12.0, -23.0];
} on InvalidPriceException {
foundException = true;
} catch (e) {
print('Tried setting a negative price and received a ${e.runtimeType} \n instead of an InvalidPriceException.');
return;
}
if (!foundException) {
print('Tried setting a negative price \n and didn\'t get an InvalidPriceException.');
return;
}
final secondCart = ShoppingCart();
try {
secondCart.prices = [1.0, 2.0, 3.0];
} catch(e) {
print('Tried setting prices with a valid list, \n but received an exception: ${e.runtimeType}.');
return;
}
if (secondCart._prices.length != 3) {
print('Tried setting prices with a list of three values, \n but _prices ended up having length ${secondCart._prices.length}.');
return;
}
if (secondCart._prices[0] != 1.0 || secondCart._prices[1] != 2.0 || secondCart._prices[2] != 3.0) {
final vals = secondCart._prices.map((p) => p.toString()).join(', ');
print('Tried setting prices with a list of three values (1, 2, 3), \n but incorrect ones ended up in the price list ($vals) .');
return;
}
var sum = 0.0;
try {
sum = secondCart.total;
} catch (e) {
print('Tried to get total, but received an exception: ${e.runtimeType}.');
return;
}
if (sum != 6.0) {
print('After setting prices to (1, 2, 3), total returned $sum instead of 6.');
return;
}
print('Success!');
}
getter 和 setter 示例的解决方案
有两个函数对本练习很有用。一个是 fold
,它可以将列表缩减为单个值(用它来计算总和)。另一个是 any
,它可以使用你提供的函数检查列表中的每个项目(用它来检查 prices setter 中是否存在任何负价格)。
// Add a "total" getter here:
double get total => _prices.fold(0, (e, t) => e + t);
// Add a "prices" setter here:
set prices(List<double> value) {
if (value.any((p) => p < 0)) {
throw InvalidPriceException();
}
_prices = value;
}
可选位置参数
#Dart 有两种函数参数:位置参数和命名参数。位置参数是你可能熟悉的类型
int sumUp(int a, int b, int c) {
return a + b + c;
}
// ···
int total = sumUp(1, 2, 3);
使用 Dart,你可以通过将这些位置参数括在方括号中来使它们成为可选的
int sumUpToFive(int a, [int? b, int? c, int? d, int? e]) {
int sum = a;
if (b != null) sum += b;
if (c != null) sum += c;
if (d != null) sum += d;
if (e != null) sum += e;
return sum;
}
// ···
int total = sumUpToFive(1, 2);
int otherTotal = sumUpToFive(1, 2, 3, 4, 5);
可选的位置参数始终位于函数参数列表的最后。除非你提供其他默认值,否则它们的默认值为 null
int sumUpToFive(int a, [int b = 2, int c = 3, int d = 4, int e = 5]) {
// ···
}
void main() {
int newTotal = sumUpToFive(1);
print(newTotal); // <-- prints 15
}
代码示例
#实现一个名为 joinWithCommas()
的函数,它接受 1 到 5 个整数,然后返回一个由逗号分隔的这些数字的字符串。以下是一些函数调用和返回值的示例
函数调用 | 返回值 |
---|---|
joinWithCommas(1) | '1' |
joinWithCommas(1, 2, 3) | '1,2,3' |
joinWithCommas(1, 1, 1, 1, 1) | '1,1,1,1,1' |
String joinWithCommas(int a, [int? b, int? c, int? d, int? e]) {
return TODO();
}
// Tests your solution (Don't edit!):
void main() {
final errs = <String>[];
try {
final value = joinWithCommas(1);
if (value != '1') {
errs.add('Tried calling joinWithCommas(1) \n and got $value instead of the expected (\'1\').');
}
} on UnimplementedError {
print('Tried to call joinWithCommas but failed. \n Did you implement the method?');
return;
} catch (e) {
print('Tried calling joinWithCommas(1), \n but encountered an exception: ${e.runtimeType}.');
return;
}
try {
final value = joinWithCommas(1, 2, 3);
if (value != '1,2,3') {
errs.add('Tried calling joinWithCommas(1, 2, 3) \n and got $value instead of the expected (\'1,2,3\').');
}
} on UnimplementedError {
print('Tried to call joinWithCommas but failed. \n Did you implement the method?');
return;
} catch (e) {
print('Tried calling joinWithCommas(1, 2 ,3), \n but encountered an exception: ${e.runtimeType}.');
return;
}
try {
final value = joinWithCommas(1, 2, 3, 4, 5);
if (value != '1,2,3,4,5') {
errs.add('Tried calling joinWithCommas(1, 2, 3, 4, 5) \n and got $value instead of the expected (\'1,2,3,4,5\').');
}
} on UnimplementedError {
print('Tried to call joinWithCommas but failed. \n Did you implement the method?');
return;
} catch (e) {
print('Tried calling stringify(1, 2, 3, 4 ,5), \n but encountered an exception: ${e.runtimeType}.');
return;
}
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
}
位置参数示例的解决方案
如果调用者没有提供 b
、c
、d
和 e
参数,则它们为 null。因此,重要的是在将这些参数添加到最终字符串之前检查它们是否为 null
。
String joinWithCommas(int a, [int? b, int? c, int? d, int? e]) {
var total = '$a';
if (b != null) total = '$total,$b';
if (c != null) total = '$total,$c';
if (d != null) total = '$total,$d';
if (e != null) total = '$total,$e';
return total;
}
命名参数
#在参数列表的末尾使用花括号语法,你可以定义具有名称的参数。
命名参数是可选的,除非它们被明确标记为 required
。
void printName(String firstName, String lastName, {String? middleName}) {
print('$firstName ${middleName ?? ''} $lastName');
}
void main() {
printName('Dash', 'Dartisan');
printName('John', 'Smith', middleName: 'Who');
// Named arguments can be placed anywhere in the argument list
printName('John', middleName: 'Who', 'Smith');
}
正如你可能预期的那样,可空命名参数的默认值为 null
,但你可以提供自定义默认值。
如果参数的类型不可为空,则必须提供默认值(如下面的代码所示)或将参数标记为 required
(如构造函数部分所示)。
void printName(String firstName, String lastName, {String middleName = ''}) {
print('$firstName $middleName $lastName');
}
函数不能同时具有可选的位置参数和命名参数。
代码示例
#向 MyDataObject
类添加一个 copyWith()
实例方法。它应该采用三个命名、可空参数
int? newInt
String? newString
double? newDouble
你的 copyWith()
方法应该根据当前实例返回一个新的 MyDataObject
,并将来自前面参数(如果有)的数据复制到对象的属性中。例如,如果 newInt
不为 null,则将其值复制到 anInt
中。
忽略 DartPad 中的所有初始错误。
class MyDataObject {
final int anInt;
final String aString;
final double aDouble;
MyDataObject({
this.anInt = 1,
this.aString = 'Old!',
this.aDouble = 2.0,
});
// TODO: Add your copyWith method here:
}
// Tests your solution (Don't edit!):
void main() {
final source = MyDataObject();
final errs = <String>[];
try {
final copy = source.copyWith(newInt: 12, newString: 'New!', newDouble: 3.0);
if (copy.anInt != 12) {
errs.add('Called copyWith(newInt: 12, newString: \'New!\', newDouble: 3.0), \n and the new object\'s anInt was ${copy.anInt} rather than the expected value (12).');
}
if (copy.aString != 'New!') {
errs.add('Called copyWith(newInt: 12, newString: \'New!\', newDouble: 3.0), \n and the new object\'s aString was ${copy.aString} rather than the expected value (\'New!\').');
}
if (copy.aDouble != 3) {
errs.add('Called copyWith(newInt: 12, newString: \'New!\', newDouble: 3.0), \n and the new object\'s aDouble was ${copy.aDouble} rather than the expected value (3).');
}
} catch (e) {
print('Called copyWith(newInt: 12, newString: \'New!\', newDouble: 3.0) \n and got an exception: ${e.runtimeType}');
}
try {
final copy = source.copyWith();
if (copy.anInt != 1) {
errs.add('Called copyWith(), and the new object\'s anInt was ${copy.anInt} \n rather than the expected value (1).');
}
if (copy.aString != 'Old!') {
errs.add('Called copyWith(), and the new object\'s aString was ${copy.aString} \n rather than the expected value (\'Old!\').');
}
if (copy.aDouble != 2) {
errs.add('Called copyWith(), and the new object\'s aDouble was ${copy.aDouble} \n rather than the expected value (2).');
}
} catch (e) {
print('Called copyWith() and got an exception: ${e.runtimeType}');
}
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
}
命名参数示例的解决方案
copyWith
方法出现在许多类和库中。你的方法应该做几件事:使用可选的命名参数,创建一个新的 MyDataObject
实例,并使用参数中的数据填充它(如果参数为 null,则使用当前实例中的数据)。这是一个练习 ??
运算符的机会!
MyDataObject copyWith({int? newInt, String? newString, double? newDouble}) {
return MyDataObject(
anInt: newInt ?? this.anInt,
aString: newString ?? this.aString,
aDouble: newDouble ?? this.aDouble,
);
}
异常
#Dart 代码可以抛出和捕获异常。与 Java 不同,Dart 的所有异常都是未经检查的。方法不声明它们可能抛出的异常,并且你不需要捕获任何异常。
Dart 提供了 Exception
和 Error
类型,但你可以抛出任何非空对象
throw Exception('Something bad happened.');
throw 'Waaaaaaah!';
在处理异常时使用 try
、on
和 catch
关键字
try {
breedMoreLlamas();
} on OutOfLlamasException {
// A specific exception
buyMoreLlamas();
} on Exception catch (e) {
// Anything else that is an exception
print('Unknown exception: $e');
} catch (e) {
// No specified type, handles all
print('Something really unknown: $e');
}
try
关键字的工作方式与大多数其他语言中的相同。使用 on
关键字按类型筛选特定异常,使用 catch
关键字获取对异常对象的引用。
如果你无法完全处理异常,请使用 rethrow
关键字传播异常
try {
breedMoreLlamas();
} catch (e) {
print('I was just trying to breed llamas!');
rethrow;
}
要执行代码,无论是否抛出异常,请使用 finally
try {
breedMoreLlamas();
} catch (e) {
// ... handle exception ...
} finally {
// Always clean up, even if an exception is thrown.
cleanLlamaStalls();
}
代码示例
#实现下面的 tryFunction()
。它应该执行一个不可靠的方法,然后执行以下操作
- 如果
untrustworthy()
抛出一个ExceptionWithMessage
,则使用异常类型和消息调用logger.logException
(尝试使用on
和catch
)。 - 如果
untrustworthy()
抛出一个Exception
,则使用异常类型调用logger.logException
(尝试为此使用on
)。 - 如果
untrustworthy()
抛出任何其他对象,则不要捕获异常。 - 在所有内容都被捕获和处理后,调用
logger.doneLogging
(尝试使用finally
)。
typedef VoidFunction = void Function();
class ExceptionWithMessage {
final String message;
const ExceptionWithMessage(this.message);
}
// Call logException to log an exception, and doneLogging when finished.
abstract class Logger {
void logException(Type t, [String? msg]);
void doneLogging();
}
void tryFunction(VoidFunction untrustworthy, Logger logger) {
try {
untrustworthy();
} on ExceptionWithMessage catch (e) {
logger.logException(e.runtimeType, e.message);
} on Exception catch (e) {
logger.logException(e.runtimeType);
} finally {
logger.doneLogging();
}
}
// Tests your solution (Don't edit!):
class MyLogger extends Logger {
Type? lastType;
String lastMessage = '';
bool done = false;
void logException(Type t, [String? message]) {
lastType = t;
lastMessage = message ?? lastMessage;
}
void doneLogging() => done = true;
}
void main() {
final errs = <String>[];
var logger = MyLogger();
try {
tryFunction(() => throw Exception(), logger);
if ('${logger.lastType}' != 'Exception' && '${logger.lastType}' != '_Exception') {
errs.add('Untrustworthy threw an Exception, but a different type was logged: \n ${logger.lastType}.');
}
if (logger.lastMessage != '') {
errs.add('Untrustworthy threw an Exception with no message, but a message \n was logged anyway: \'${logger.lastMessage}\'.');
}
if (!logger.done) {
errs.add('Untrustworthy threw an Exception, \n and doneLogging() wasn\'t called afterward.');
}
} catch (e) {
print('Untrustworthy threw an exception, and an exception of type \n ${e.runtimeType} was unhandled by tryFunction.');
}
logger = MyLogger();
try {
tryFunction(() => throw ExceptionWithMessage('Hey!'), logger);
if (logger.lastType != ExceptionWithMessage) {
errs.add('Untrustworthy threw an ExceptionWithMessage(\'Hey!\'), but a \n different type was logged: ${logger.lastType}.');
}
if (logger.lastMessage != 'Hey!') {
errs.add('Untrustworthy threw an ExceptionWithMessage(\'Hey!\'), but a \n different message was logged: \'${logger.lastMessage}\'.');
}
if (!logger.done) {
errs.add('Untrustworthy threw an ExceptionWithMessage(\'Hey!\'), \n and doneLogging() wasn\'t called afterward.');
}
} catch (e) {
print('Untrustworthy threw an ExceptionWithMessage(\'Hey!\'), \n and an exception of type ${e.runtimeType} was unhandled by tryFunction.');
}
logger = MyLogger();
bool caughtStringException = false;
try {
tryFunction(() => throw 'A String', logger);
} on String {
caughtStringException = true;
}
if (!caughtStringException) {
errs.add('Untrustworthy threw a string, and it was incorrectly handled inside tryFunction().');
}
logger = MyLogger();
try {
tryFunction(() {}, logger);
if (logger.lastType != null) {
errs.add('Untrustworthy didn\'t throw an Exception, \n but one was logged anyway: ${logger.lastType}.');
}
if (logger.lastMessage != '') {
errs.add('Untrustworthy didn\'t throw an Exception with no message, \n but a message was logged anyway: \'${logger.lastMessage}\'.');
}
if (!logger.done) {
errs.add('Untrustworthy didn\'t throw an Exception, \n but doneLogging() wasn\'t called afterward.');
}
} catch (e) {
print('Untrustworthy didn\'t throw an exception, \n but an exception of type ${e.runtimeType} was unhandled by tryFunction anyway.');
}
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
}
异常示例的解决方案
这个练习看起来很棘手,但它实际上是一个大的 try
语句。在 try
内部调用 untrustworthy
,然后使用 on
、catch
和 finally
来捕获异常并调用 logger 上的方法。
void tryFunction(VoidFunction untrustworthy, Logger logger) {
try {
untrustworthy();
} on ExceptionWithMessage catch (e) {
logger.logException(e.runtimeType, e.message);
} on Exception {
logger.logException(Exception);
} finally {
logger.doneLogging();
}
}
在构造函数中使用 this
#Dart 提供了一个方便的快捷方式来为构造函数中的属性赋值:在声明构造函数时使用 this.propertyName
class MyColor {
int red;
int green;
int blue;
MyColor(this.red, this.green, this.blue);
}
final color = MyColor(80, 80, 128);
此技术也适用于命名参数。属性名称成为参数的名称
class MyColor {
...
MyColor({required this.red, required this.green, required this.blue});
}
final color = MyColor(red: 80, green: 80, blue: 80);
在前面的代码中,red
、green
和 blue
被标记为 required
,因为这些 int
值不能为 null。如果添加默认值,则可以省略 required
MyColor([this.red = 0, this.green = 0, this.blue = 0]);
// or
MyColor({this.red = 0, this.green = 0, this.blue = 0});
代码示例
#向 MyClass
添加一个单行构造函数,使用 this.
语法接收和分配类所有三个属性的值。
忽略 DartPad 中的所有初始错误。
class MyClass {
final int anInt;
final String aString;
final double aDouble;
// TODO: Create the constructor here.
}
// Tests your solution (Don't edit!):
void main() {
final errs = <String>[];
try {
final obj = MyClass(1, 'two', 3);
if (obj.anInt != 1) {
errs.add('Called MyClass(1, \'two\', 3) and got an object with anInt of ${obj.anInt} \n instead of the expected value (1).');
}
if (obj.anInt != 1) {
errs.add('Called MyClass(1, \'two\', 3) and got an object with aString of \'${obj.aString}\' \n instead of the expected value (\'two\').');
}
if (obj.anInt != 1) {
errs.add('Called MyClass(1, \'two\', 3) and got an object with aDouble of ${obj.aDouble} \n instead of the expected value (3).');
}
} catch (e) {
print('Called MyClass(1, \'two\', 3) and got an exception \n of type ${e.runtimeType}.');
}
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
}
this
示例的解决方案
此练习有一个单行解决方案。按顺序声明构造函数,其参数为 this.anInt
、this.aString
和 this.aDouble
。
MyClass(this.anInt, this.aString, this.aDouble);
初始化列表
#有时,当你实现构造函数时,你需要在构造函数体执行之前进行一些设置。例如,final 字段必须在构造函数体执行之前具有值。在初始化列表中完成此工作,初始化列表位于构造函数的签名和主体之间
Point.fromJson(Map<String, double> json)
: x = json['x']!,
y = json['y']! {
print('In Point.fromJson(): ($x, $y)');
}
初始化列表也是放置断言的方便位置,断言仅在开发期间运行
NonNegativePoint(this.x, this.y)
: assert(x >= 0),
assert(y >= 0) {
print('I just made a NonNegativePoint: ($x, $y)');
}
代码示例
#完成下面的 FirstTwoLetters
构造函数。使用初始化列表将 word
中的前两个字符分配给 letterOne
和 LetterTwo
属性。作为额外奖励,添加一个 assert
来捕获少于两个字符的单词。
忽略 DartPad 中的所有初始错误。
class FirstTwoLetters {
final String letterOne;
final String letterTwo;
// TODO: Create a constructor with an initializer list here:
FirstTwoLetters(String word)
}
// Tests your solution (Don't edit!):
void main() {
final errs = <String>[];
try {
final result = FirstTwoLetters('My String');
if (result.letterOne != 'M') {
errs.add('Called FirstTwoLetters(\'My String\') and got an object with \n letterOne equal to \'${result.letterOne}\' instead of the expected value (\'M\').');
}
if (result.letterTwo != 'y') {
errs.add('Called FirstTwoLetters(\'My String\') and got an object with \n letterTwo equal to \'${result.letterTwo}\' instead of the expected value (\'y\').');
}
} catch (e) {
errs.add('Called FirstTwoLetters(\'My String\') and got an exception \n of type ${e.runtimeType}.');
}
bool caughtException = false;
try {
FirstTwoLetters('');
} catch (e) {
caughtException = true;
}
if (!caughtException) {
errs.add('Called FirstTwoLetters(\'\') and didn\'t get an exception \n from the failed assertion.');
}
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
}
初始化列表示例的解决方案
需要进行两次赋值:letterOne
应分配 word[0]
,letterTwo
应分配 word[1]
。
FirstTwoLetters(String word)
: assert(word.length >= 2),
letterOne = word[0],
letterTwo = word[1];
命名构造函数
#为了允许类具有多个构造函数,Dart 支持命名构造函数
class Point {
double x, y;
Point(this.x, this.y);
Point.origin()
: x = 0,
y = 0;
}
要使用命名构造函数,请使用其全名调用它
final myPoint = Point.origin();
代码示例
#为 Color
类提供一个名为 Color.black
的构造函数,将所有三个属性设置为零。
忽略 DartPad 中的所有初始错误。
class Color {
int red;
int green;
int blue;
Color(this.red, this.green, this.blue);
// TODO: Create a named constructor called "Color.black" here:
}
// Tests your solution (Don't edit!):
void main() {
final errs = <String>[];
try {
final result = Color.black();
if (result.red != 0) {
errs.add('Called Color.black() and got a Color with red equal to \n ${result.red} instead of the expected value (0).');
}
if (result.green != 0) {
errs.add('Called Color.black() and got a Color with green equal to \n ${result.green} instead of the expected value (0).');
}
if (result.blue != 0) {
errs.add('Called Color.black() and got a Color with blue equal to \n ${result.blue} instead of the expected value (0).');
}
} catch (e) {
print('Called Color.black() and got an exception of type \n ${e.runtimeType}.');
return;
}
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
}
命名构造函数示例的解决方案
构造函数的声明应该以 Color.black():
开头。在初始化列表(冒号之后)中,将 red
、green
和 blue
设置为 0
。
Color.black()
: red = 0,
green = 0,
blue = 0;
工厂构造函数
#Dart 支持工厂构造函数,它可以返回子类型甚至 null。要创建工厂构造函数,请使用 factory
关键字
class Square extends Shape {}
class Circle extends Shape {}
class Shape {
Shape();
factory Shape.fromTypeName(String typeName) {
if (typeName == 'square') return Square();
if (typeName == 'circle') return Circle();
throw ArgumentError('Unrecognized $typeName');
}
}
代码示例
#替换工厂构造函数 IntegerHolder.fromList
中的 TODO();
行,以返回以下内容
- 如果列表具有**一个**值,则使用该值创建
IntegerSingle
实例。 - 如果列表具有**两个**值,则使用这些值按顺序创建
IntegerDouble
实例。 - 如果列表具有**三个**值,则使用这些值按顺序创建
IntegerTriple
实例。 - 否则,抛出一个
Error
。
如果成功,控制台应该显示 Success!
。
class IntegerHolder {
IntegerHolder();
// Implement this factory constructor.
factory IntegerHolder.fromList(List<int> list) {
TODO();
}
}
class IntegerSingle extends IntegerHolder {
final int a;
IntegerSingle(this.a);
}
class IntegerDouble extends IntegerHolder {
final int a;
final int b;
IntegerDouble(this.a, this.b);
}
class IntegerTriple extends IntegerHolder {
final int a;
final int b;
final int c;
IntegerTriple(this.a, this.b, this.c);
}
// Tests your solution (Don't edit from this point to end of file):
void main() {
final errs = <String>[];
// Run 5 tests to see which values have valid integer holders
for (var tests = 0; tests < 5; tests++) {
if (!testNumberOfArgs(errs, tests)) return;
}
// The goal is no errors with values 1 to 3,
// but have errors with values 0 and 4.
// The testNumberOfArgs method adds to the errs array if
// the values 1 to 3 have an error and
// the values 0 and 4 don't have an error
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
}
bool testNumberOfArgs(List<String> errs, int count) {
bool _threw = false;
final ex = List.generate(count, (index) => index + 1);
final callTxt = "IntegerHolder.fromList(${ex})";
try {
final obj = IntegerHolder.fromList(ex);
final String vals = count == 1 ? "value" : "values";
// Uncomment the next line if you want to see the results realtime
// print("Testing with ${count} ${vals} using ${obj.runtimeType}.");
testValues(errs, ex, obj, callTxt);
} on Error {
_threw = true;
} catch (e) {
switch (count) {
case (< 1 && > 3):
if (!_threw) {
errs.add('Called ${callTxt} and it didn\'t throw an Error.');
}
default:
errs.add('Called $callTxt and received an Error.');
}
}
return true;
}
void testValues(List<String> errs, List<int> expectedValues, IntegerHolder obj,
String callText) {
for (var i = 0; i < expectedValues.length; i++) {
int found;
if (obj is IntegerSingle) {
found = obj.a;
} else if (obj is IntegerDouble) {
found = i == 0 ? obj.a : obj.b;
} else if (obj is IntegerTriple) {
found = i == 0
? obj.a
: i == 1
? obj.b
: obj.c;
} else {
throw ArgumentError(
"This IntegerHolder type (${obj.runtimeType}) is unsupported.");
}
if (found != expectedValues[i]) {
errs.add(
"Called $callText and got a ${obj.runtimeType} " +
"with a property at index $i value of $found " +
"instead of the expected (${expectedValues[i]}).");
}
}
}
工厂构造函数示例的解决方案
在工厂构造函数内部,检查列表的长度,然后根据需要创建并返回 IntegerSingle
、IntegerDouble
或 IntegerTriple
。
用以下代码块替换 TODO();
。
switch (list.length) {
case 1:
return IntegerSingle(list[0]);
case 2:
return IntegerDouble(list[0], list[1]);
case 3:
return IntegerTriple(list[0], list[1], list[2]);
default:
throw ArgumentError("List must between 1 and 3 items. This list was ${list.length} items.");
}
重定向构造函数
#有时,构造函数的唯一目的是重定向到同一类中的另一个构造函数。重定向构造函数的主体为空,构造函数调用出现在冒号 (:
) 之后。
class Automobile {
String make;
String model;
int mpg;
// The main constructor for this class.
Automobile(this.make, this.model, this.mpg);
// Delegates to the main constructor.
Automobile.hybrid(String make, String model) : this(make, model, 60);
// Delegates to a named constructor
Automobile.fancyHybrid() : this.hybrid('Futurecar', 'Mark 2');
}
代码示例
#还记得上面的 Color
类吗?创建一个名为 black
的命名构造函数,但不要手动分配属性,而是将其重定向到以零作为参数的默认构造函数。
忽略 DartPad 中的所有初始错误。
class Color {
int red;
int green;
int blue;
Color(this.red, this.green, this.blue);
// TODO: Create a named constructor called "black" here
// and redirect it to call the existing constructor
}
// Tests your solution (Don't edit!):
void main() {
final errs = <String>[];
try {
final result = Color.black();
if (result.red != 0) {
errs.add('Called Color.black() and got a Color with red equal to \n ${result.red} instead of the expected value (0).');
}
if (result.green != 0) {
errs.add('Called Color.black() and got a Color with green equal to \n ${result.green} instead of the expected value (0).');
}
if (result.blue != 0) {
errs.add('Called Color.black() and got a Color with blue equal to \n ${result.blue} instead of the expected value (0).');
}
} catch (e) {
print('Called Color.black() and got an exception of type ${e.runtimeType}.');
return;
}
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
}
重定向构造函数示例的解决方案
你的构造函数应该重定向到 this(0, 0, 0)
。
Color.black() : this(0, 0, 0);
常量构造函数
#如果你的类生成永不更改的对象,则可以使这些对象成为编译时常量。为此,定义一个 const
构造函数,并确保所有实例变量都是 final 的。
class ImmutablePoint {
static const ImmutablePoint origin = ImmutablePoint(0, 0);
final int x;
final int y;
const ImmutablePoint(this.x, this.y);
}
代码示例
#修改 Recipe
类,使其实例可以成为常量,并创建一个常量构造函数,执行以下操作
- 具有三个参数:
ingredients
、calories
和milligramsOfSodium
(按此顺序)。 - 使用
this.
语法自动将参数值赋值给同名的对象属性。 - 是常量,在构造函数声明中的
Recipe
之前使用const
关键字。
忽略 DartPad 中的所有初始错误。
class Recipe {
List<String> ingredients;
int calories;
double milligramsOfSodium;
// TODO: Create a const constructor here"
}
// Tests your solution (Don't edit!):
void main() {
final errs = <String>[];
try {
const obj = Recipe(['1 egg', 'Pat of butter', 'Pinch salt'], 120, 200);
if (obj.ingredients.length != 3) {
errs.add('Called Recipe([\'1 egg\', \'Pat of butter\', \'Pinch salt\'], 120, 200) \n and got an object with ingredient list of length ${obj.ingredients.length} rather than the expected length (3).');
}
if (obj.calories != 120) {
errs.add('Called Recipe([\'1 egg\', \'Pat of butter\', \'Pinch salt\'], 120, 200) \n and got an object with a calorie value of ${obj.calories} rather than the expected value (120).');
}
if (obj.milligramsOfSodium != 200) {
errs.add('Called Recipe([\'1 egg\', \'Pat of butter\', \'Pinch salt\'], 120, 200) \n and got an object with a milligramsOfSodium value of ${obj.milligramsOfSodium} rather than the expected value (200).');
}
} catch (e) {
print('Tried calling Recipe([\'1 egg\', \'Pat of butter\', \'Pinch salt\'], 120, 200) \n and received a null.');
}
if (errs.isEmpty) {
print('Success!');
} else {
errs.forEach(print);
}
}
常量构造函数示例的解决方案
要使构造函数为常量,您需要将所有属性设为final
。
class Recipe {
final List<String> ingredients;
final int calories;
final double milligramsOfSodium;
const Recipe(this.ingredients, this.calories, this.milligramsOfSodium);
}
下一步是什么?
#我们希望您喜欢使用本教程来学习或测试您对 Dart 语言一些最有趣功能的了解。
接下来您可以尝试以下内容
除非另有说明,否则本网站上的文档反映的是 Dart 3.5.3。页面上次更新于 2024-08-04。 查看源代码 或 报告问题.